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NN
2
NH
20 tháng 8 2025
(-2/3)² * 5/13 - 8/13 : (-9/4) - 1/2
= 4/9 * 5/13 + 8/13 * 4/9 - 1/2
= 4/9 * (5/13 + 8/13) - 1/2
= 4/9 * 1 - 1/2
= 4/9 - 1/2
= 8/18 - 9/18
= -1/18
20 tháng 8 2025
=(-4/9).5/13-(-32/117)-1/2
=-20/27-(-32/117)-1/2
=(-164/351)-1/2
=-679/702
ko chắc lắm tham khảo thôi nha!
LT
5
24 tháng 9 2019
\(\frac{5}{13}\times\frac{-2}{3}-\frac{8}{13}\times\frac{2}{3}\)
\(=\frac{-5}{13}\times\frac{2}{3}-\frac{8}{13}\times\frac{2}{3}\)
\(=\frac{2}{3}\left(\frac{-5}{13}-\frac{8}{13}\right)\)
\(=\frac{2}{3}\times\left(-1\right)=\frac{-2}{3}\)
24 tháng 9 2019
=\(\frac{-5}{13}\).\(\frac{2}{3}\)-\(\frac{8}{13}\).\(\frac{2}{3}\)
= \(\frac{2}{3}\).(\(\frac{-5}{13}\)-\(\frac{8}{13}\))
=\(\frac{2}{3}\). 1
=\(\frac{2}{3}\)
CN
1
TG
17 tháng 8 2020
a) \(\frac{3}{4}+\left(-\frac{1}{8}\right)\)
\(=\frac{6}{8}-\frac{1}{8}=\frac{5}{8}\)
b) \(-\frac{5}{12}+\left(-\frac{7}{24}\right)=\left(-\frac{10}{24}\right)+\left(-\frac{7}{24}\right)=-\frac{17}{24}\)
c) \(1+\left(-\frac{7}{8}\right)=\frac{8}{8}-\frac{7}{8}=\frac{1}{8}\)
d) \(\frac{13}{30}-\frac{1}{3}=\frac{13}{30}-\frac{10}{30}=\frac{3}{30}\)
e) \(\frac{4}{21}-\left(-\frac{5}{28}\right)=\frac{4}{21}+\frac{5}{28}=\frac{16}{84}+\frac{15}{84}=\frac{31}{84}\)
NL
Nguyễn Lê Phước Thịnh
CTVHS
27 tháng 5 2022
a: \(\left(\dfrac{5}{6}\right)^6\cdot\left(\dfrac{6}{5}\right)^6\cdot\left(\dfrac{6}{5}\right)^2=\left(\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^6\cdot\dfrac{36}{25}=\dfrac{36}{25}\)
b: \(=-\left(\dfrac{13}{8}\right)^3\cdot\left(\dfrac{32}{13}\right)^3\cdot\dfrac{32}{13}\)
\(=-\left(\dfrac{13}{8}\cdot\dfrac{32}{13}\right)^3\cdot\dfrac{32}{13}=-4^3\cdot\dfrac{32}{13}=\dfrac{-2048}{13}\)
c: \(=\left(0.1\right)^7\cdot10^{13}=\left(0.1\cdot10\right)^7\cdot10^6=10^6\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
5 tháng 10 2025
Câu a:
(4\(\frac{5}{37}\) - 3\(\frac45\) + 8\(\frac{15}{29}\)) - (3\(\frac{5}{37}\) - 6\(\frac{14}{29}\))
= 4\(\frac{5}{37}\) - 3\(\frac45\) + 8\(\frac{15}{29}\) - 3\(\frac{15}{37}\) + 6\(\frac{14}{29}\)
= (4 - 3) + (\(\frac{5}{37}-\frac{5}{37}\)) + (8 + 6) + (\(\frac{15}{29}\) + \(\frac{14}{29}\)) - 3 - \(\frac45\)
= 1 + 0 + 14 + 1 - 3 - \(\frac45\)
= 1 + 14 + 1 - 3 - \(\frac45\)
= 15 + 1 - 3 - \(\frac45\)
= 16 - 3 - \(\frac45\)
= 13 - \(\frac45\)
= \(\frac{61}{5}\)
27 tháng 6 2017
a, \(\dfrac{3}{4}+x=\dfrac{8}{13}\)
\(x=\dfrac{8}{13}-\dfrac{3}{4}\)
\(x=-\dfrac{7}{52}\)
b,\(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
\(\dfrac{2}{5}+x=\dfrac{11}{12}-\dfrac{2}{3}\)
\(\dfrac{2}{5}+x=\dfrac{1}{4}\)
\(x=\dfrac{1}{4}-\dfrac{2}{5}\)
\(x=-\dfrac{3}{20}\)
c, \(2x\left(x-\dfrac{1}{7}\right)=0\)
\(2x-\dfrac{1}{7}=0\)
\(x-\dfrac{1}{7}=0:2\)
\(x-\dfrac{1}{7}=0\)
\(x=0-\dfrac{1}{7}\)
\(x=\dfrac{1}{7}\)
d, \(\dfrac{3}{4}+\dfrac{1}{4}\div x=\dfrac{2}{5}\)
\(\left(\dfrac{3}{4}+\dfrac{1}{4}\right):x=\dfrac{2}{5}\)
\(1:x=\dfrac{2}{5}\)
\(x=1:\dfrac{2}{5}\)
\(x=\dfrac{5}{2}\)
27 tháng 6 2017
a) \(\dfrac{3}{4}+x=\dfrac{8}{13}\)\(\Leftrightarrow\) \(x=\dfrac{8}{13}-\dfrac{3}{4}=\dfrac{-7}{52}\) vậy \(x=\dfrac{-7}{52}\)
b) \(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\) \(\Leftrightarrow\) \(\dfrac{11}{12}-\dfrac{2}{5}-x=\dfrac{2}{3}\) \(\Leftrightarrow\) \(x=\dfrac{11}{12}-\dfrac{2}{5}-\dfrac{2}{3}=\dfrac{-3}{20}\) vậy \(x=\dfrac{-3}{20}\)
c) \(2x\left(x-\dfrac{1}{7}\right)=0\) \(\Leftrightarrow\) \(2x^2-\dfrac{2}{7}x=0\)
\(\Delta\) = \(\left(\dfrac{-2}{7}\right)^2-4.2.0=\dfrac{4}{49}>0\)
\(\Rightarrow\) phương trình có 2 nghiệm phân biệt
\(x_1=\dfrac{\dfrac{2}{7}+\sqrt{\dfrac{4}{49}}}{4}=\dfrac{1}{7}\)
\(x_2=\dfrac{\dfrac{2}{7}-\sqrt{\dfrac{4}{49}}}{4}=0\)
vậy \(x=0;x=\dfrac{1}{7}\)
A
7 tháng 11 2018
( -1,25) . 14,7. ( -8 )
= \(\frac{-5}{4}\). \(\frac{147}{10}\)\(.\frac{\left(-8\right)}{1}\)
= \(\frac{\left(-5\right).147.\left(-8\right)}{4.10.1}.\)
= \(\frac{\left[\left(-5\right).\left(-8\right)\right].147}{\left(4.10\right).1}\)
= \(\left[\frac{-5}{4}.\frac{-8}{10}\right].147\)
=147
-11